導讀:1建站知識本篇文章是對Oracle查詢和刪除JOB的SQL的實現方法進行了詳細的分析介紹，需要的朋友參考下營銷型網站建設seo網站優化培訓。

查詢及刪除重復記錄的SQL語句1、查找表中多余的重復記錄，重復記錄是根據單個字段（peopleId）來判斷select * from peoplewhere peopleId in (select   peopleId from   people group by   peopleId having count(peopleId) > 1)2、刪除表中多余的重復記錄，營銷型網站建設重復記錄是根據單個字段（peopleId）來判斷，只留有rowid最小的記錄delete from people where peopleId in (select   peopleId from people group by   peopleId   having count(peopleId) > 1)and rowid not in (select min(rowid) from   people group by peopleId having count(peopleId )>1)注:rowid為oracle自帶不用該.....3、查找表中多余的重復記錄（多個字段） select * from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1) 4、刪除表中多余的重復記錄（多個字段），只留有rowid最小的記錄delete from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having coun網站建設哪家好t(*) > 1)網站推廣優化seoand rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)5、查找表中多余的重復記錄（多個字段），不包含rowid最小的記錄select * from vitae awhere (a.peopleId,a.seq) in   (select peopleId,seq from vitae group by peopleId,seq having count(*) > 1)and rowid not in (select min(rowid) from vitae group by peopleId,seq having count(*)>1)(二)比方說在A表中存在一個字段“name”，而且不同記錄之間的“name”值有可能會相同，現在就是需要查詢出在該表中的各記錄之間，“name”值存在重復的項；Select Name,Count(*) from A Group By Name Having Count(*) > 1如果還查性別也相同大則如下:Select Name,sex,Count(*) from A Group By Name,sex Having Count(*) > 1(三)方法一declare @max integer,@id integerdeclare cur_rows cursor local for select 主字段,count(*) from 表名 group by 主字段 having count(*) >； 1open cur_rowsfetch cur_rows into @id,@maxwhile @@fetch ......相關營銷型網站建設seo網站優化培訓。

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