Sql學習第一天——SQL 練習題(建表/sql語句)建站知
導讀:1建站知識來自Madrid且訂單數少于3的消費者,針對這個要求作出以下:建表做題分析以及sql語句的寫法,感興趣的朋友可以參考下seo網站優化營銷型網站建設。
題目:來自Madrid且訂單數少于3的消費者
建表:
復制代碼 代碼如下:
set nocount on --當 SET NOCOUNT 為 ON 時,不返回計數(表示受 Transact-SQL 語句影響的行數)。當 SET NOCOUNT 為 OFF 時,返回計數 use SY GO if object_Id('dbo.Orders') is not null drop table dbo.Orders GO if object_Id('dbo.Customers') is not null drop table dbo.Customers GO create table dbo.Customers ( customerid char(5) not null primary key , city varchar(10) not null ); insert into dbo.Customers values('FISSA','Madrid'); insert into dbo.Customers values('FRNDO','Madrid'); insert into dbo.Customers values('KRLOS','Madrid'); insert into dbo.Customers values('MRPHS','Zion'); create table dbo.Orders ( orderid int not null primary key , customerid char(5) null references customers(customerid) ) insert into dbo.Orders values(1,'FRNDO'); insert into dbo.Orders value高端網站建設s(2,'FRNDO'); insert into dbo.Orders values(3,'KRLOS'); insert into dbo.Orders values(4,'KRLOS'); insert into dbo.Orders values(5,'KRLOS'); insert into dbo.Orders values(6,'MRPHS'); insert into dbo.Orders values(7,null);
---百度seo網站優化---------------------------------------------------------------------------------------------------------------------------做題分析:
復制代碼 代碼如下:
select customerid as 消費者,count(customerid) as 訂單數 from dbo.Orders where customerid in ( select customerid from dbo.Customers where city = 'Madrid') group by customerid having count(customerid) < 3
結果如圖所示:--第一次想到的答案,突然發現少了一個來自Madrid的FISSA訂單,FISSA訂單數量為0,所以在Orders表中沒有出現,所以上面的寫法會少一個.--推網站seo優化課程翻了上面的答案,又想到了用表的連接,而用內連接出現的情況會和上面的一樣,所以我選擇了左連接,如下:
復制代碼 代碼如下:
select C.customerid as 消費者,count(O.customerid) as 訂單數 from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid where C.city= 'Madrid' group by C.customerid having count(C.customerid) < 3
結果如圖所示:--查詢發現是正確的。--分析查看不帶條件的左連接
復制代碼 代碼如下:
select * from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid
復制代碼 代碼如下:
select * from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid
結果如圖所示:--書中給的標準答案是:
復制代碼 代碼如下:
select C.customerid , count(O.orderid) as numorders from dbo.Customers as C left join dbo.Orders as O on C.customerid = O.customerid where C.city= 'Madrid' group by C.customerid having count(O.orderid) < 3 order by numorders
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